Re: [udig-devel] How to remove all features from a resource?

[tony.roth@xxxxxx]

I found the solution after writing an email to the list:

 

static Filter NONE

in the Filter Interface is what I want

 

 

but  I have another problem:

 

I generate a resource with "createTemporaryResource(featureType)" and add some features to it. Later I want to reuse this resource (and the layer) and remove all features of this resource (using the code above). Then I add new Features to the (empty) resource but - and this takes me quite a long time to figure out - the resource has an internal envelope which is somehow depending on the map the resource (layer?) is bound to. Therefore the new Features are clipped with the (old) envelope even I set the envelope of the map to a new value. Is it possible to set the envelope / bounding box of an temporary layer manually like I can store it in a shapefile header?

 

tony roth

 

 

 

-----udig-devel-bounces@xxxxxxxxxxxxxxxxxxxxx schrieb: -----

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I want to remove all features of an ressource with:

FeatureStore fs = layer.getGeoRessource().resolve(FeatureStore.class,null);

fs.removeFeatures(Filter arg0)

Is it the correct way?

Since I want to remove all features, I do not have to filter. What can I do?

I can take a FidFilter which contains all IDs of all features but I hope there is an easier way.

tony roth

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