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Re: [ptp-user] problem with using ptp
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PTP 3.0 is no longer supported. I'd suggest trying PTP 4.0.
Regards,
Greg
On Sep 6, 2010, at 4:55 PM, ruwn wrote:
> Dear All,
>
> I installed PTP 3.0 and everything went fine. If I compile and run the
> MPI Hello World C Project, i get this output:
>
> Num processes: 1
> PI is approximately 3.1415926535904264
>
>
> If I want to compile and run my own programm (see below), the compiling
> works fine.
> But when i want to run it, the only output is:
> Process: 0
>
> I think, that I have to tell PTP to use more than 1 process, but i can't
> find the setting.
>
> When I use my shell and write:
> "mpiexec -n 4 testprogram"
> that output is produced:
> Process: 0Array D= 3.000000
> Array D= 4.000000
> Array D= 5.000000
> Array D= 6.000000
>
>
> thx and best regards
> ruwn
>
>
> here the code:
>
> #include <stdlib.h>
> #include <stdio.h>
> #include <time.h>
> #include <mpi.h>
>
> #define TAG 123
>
> int main (int argc, char **argv)
> {
> int i;
> int myrank, nprocs;
> int namelen;
> char name[MPI_MAX_PROCESSOR_NAME];
>
> MPI_Status status;
>
> /* MPI initialisieren und Argumente setzen */
> MPI_Init(&argc, &argv);
>
> /* Anzahl der Prozesse erfragen */
> MPI_Comm_size(MPI_COMM_WORLD, &nprocs);
>
> /* Eigenen Rang erfragen */
> MPI_Comm_rank(MPI_COMM_WORLD, &myrank);
>
> /* Rechnernamen erfragen */
> MPI_Get_processor_name(name, &namelen);
>
> if (myrank==0) {
> printf("Process: %i", myrank);
>
> double A[4];
> double D[4];
> for (i=0;i<4;i++)
> A[i]=i+1;
> MPI_Send(A, 4, MPI_DOUBLE, 1, 0, MPI_COMM_WORLD);
> MPI_Recv(D, 4, MPI_DOUBLE, 2, 0, MPI_COMM_WORLD, &status);
> for (i=0;i<4;i++)
> printf("Array D= %lf \n", D[i]);
> }
>
> if (myrank == 1) {
> printf("Process: %i", myrank);
> double B[4];
> MPI_Recv(B, 4, MPI_DOUBLE, 0, 0, MPI_COMM_WORLD, &status);
> for (i=0;i<4;i++)
> B[i]+=1;
> MPI_Send(B, 4, MPI_DOUBLE, 2, 0, MPI_COMM_WORLD);
> }
>
> if (myrank == 2) {
> printf("Process: %i", myrank);
> double C[4];
> MPI_Recv(C, 4, MPI_DOUBLE, 1, 0, MPI_COMM_WORLD, &status);
> for (i=0;i<4;i++)
> C[i]+=1;
> MPI_Send(C, 4, MPI_DOUBLE, 0, 0, MPI_COMM_WORLD);
> }
>
> /* MPI geordnet beenden */
> MPI_Finalize();
>
> return 0;
> }
>
>
>
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