Re: [henshin-dev] How to correctly build rules?

[Christian Krause <henshin.ck@xxxxxxxxx>]

Hi Jens,

On 10/15/2012 05:42 PM, Jens Bürger wrote:
> Am 09.10.2012 20:05, schrieb Christian Krause:
> > Hi Jens,
> >
> > Am 05.10.2012 19:29, schrieb Jens Bürger:
> > > Henshin even seems to apply a transformation, but instead of adding
> > > the desired stereotype, it (aims to) remove the two other stereotypes
> > > (the one from aNode and the CommunicationPath) -- maybe I
> > > misunderstood how transformation rules work here?
> >
> > Could it be that the stereotypes are root nodes?
>
> It seems so, because the tree of the UML-XMI looks like this:
> <?xml version="1.0" encoding="UTF-8"?>
> <xmi:XMI xmi:version="2.1"  ... >
>   <uml:Model xmi:id="idModel" name="seclinksModel">
>  ...
>   </uml:Model>
>   <UMLsec:Internet ...   />
>   <UMLsec:critical ...    />
> </xmi:XMI>
>
> > If you execute your
> > transformation programmatically, try this: call graph.getRoots()
>
> This way the application of the stereotype seems to run fine.

great.

> My only problem is: how can I save the graph? :)

This is easy. The saveEObject() method is just a convenience method. You 
can save your objects directly using the EMF API:

Resource resource = resourceSet.createResource(uri);
resource.getContents().addAll(graph.getRoots());
try {
      resource.save(null);
} catch (IOException e) {
    // ...
}

Cheers,
Christian

> The graph is a Egraph, but saveEObject does only take an EObject. The 
> only thing I can do at the moment is calling
> graph.getRoots().get(0)
> or something.
>
> Thanks,
>
> Jens
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